正确答案
T=tWH+tWL
=0.7(R1+R2)C+0.7R2C
=0.7(R1+2R2)C
=0.7×(3.9×103+2×3×103)×1×10-6s=6.93ms
f=1/T=1/(6.93×10-3)Hz=144.3Hz
tWH=0.7(R1+R2)C=0.7×(3.9×103+3×103)×1×10-6s=4.83ms
q=tWH/T×100%=(4.83/6.93)×100%=69.7%
答:该多谐振荡器的振荡周期为6.93ms、振荡频率为144.3Hz脉宽为4.83ms
及占空比为69.7%。