单选题

某正弦电压的最大值为311V,周期为0.02s、初相为30°,则该正弦电压的表达式为()

Au=220sin(314t-30°)V

Bu=220sin(314t+30°)V

Cu=311sin(314t-30°)V

Du=311sin(314t+30°)V

正确答案

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答案解析