简答题

现有(DS)=2000H,(BX)=0100H,(SI)=0002H,(20100H)=12H,(20101H)=34H,(20102H)=56H,(20103H)=78H,(21200H)=2AH,(21201H)=4CH,(21202H)=0B7H,(21203H)=65H,说明下列指令执行后AX寄存器的内容。 (1)MOVAX,1200H (2)MOVAX,BX (3)MOVAX,[1200H] (4)MOVAX,[BX] (5)MOVAX,1100H[BX] (6)MOVAX,[BX][SI] (7)MOVAX,1100H[BX][SI]

正确答案

(1)指令MOVAX,1200H执行后,(AX)=1200H(立即数操作数)。
(2)指令MOVAX,BX执行后,(AX)=0100H(寄存器操作数)。
(3)指令MOVAX,[1200H]执行后,(AX)=4C2AH(直接地址,EA=1200H)
(4)指令MOVAX,[BX]执行后,(AX)=3412H(寄存器间接寻址,EA=0100H)
(5)指令MOVAX,1100H[BX]执行后,(AX)=4C2AH(相对地址,EA=1200H)
(6)指令MOVAX,[BX][SI]执行后,(AX)=7856H(基址变址寻址,EA=0102H)
(7)指令MOVAX,1100H[BX][SI]执行后,(AX)=65B7H(相对基址变址寻址,EA=1202H)

答案解析

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